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tjc
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PostPosted: Mon Sep 18, 2006 4:55 pm 
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Joined: Thu Mar 25, 2004 11:00 am
Posts: 9551
Location: Arlington, MA
Try something like:
Code:
#!/bin/bash

DIGITS=$(echo $1 | awk '{ printf("%03d\n", $1); }' | sed -e 's/./& /g')
for digit in $DIGITS; do
    echo $digit
done

My example just produced a string on stdout, you need to capture the reformatted number and use it rather than the original...
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BluesBrian
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PostPosted: Tue Sep 19, 2006 7:47 am 
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Joined: Fri Jul 29, 2005 1:22 am
Posts: 232
Location: SF East Bay, CA
tjc wrote:
.. you need to capture the reformatted number and use it rather than the original..

That does it! Thanks! :)

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